Base | Representation |
---|---|
bin | 1000010101111010100… |
… | …0000010010000000111 |
3 | 111200221022122020120210 |
4 | 2011132220002100013 |
5 | 4322010244132210 |
6 | 145501352330503 |
7 | 13232432300064 |
oct | 2053650022007 |
9 | 450838566523 |
10 | 143321474055 |
11 | 55867265821 |
12 | 2393a0a3a33 |
13 | 10690a52666 |
14 | 6d187d7c6b |
15 | 3adc616e20 |
hex | 215ea02407 |
143321474055 has 32 divisors (see below), whose sum is σ = 242269056000. Its totient is φ = 72232049792.
The previous prime is 143321474053. The next prime is 143321474057. The reversal of 143321474055 is 550474123341.
It is an interprime number because it is at equal distance from previous prime (143321474053) and next prime (143321474057).
It is a cyclic number.
It is not a de Polignac number, because 143321474055 - 21 = 143321474053 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143321474053) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3484605 + ... + 3525494.
It is an arithmetic number, because the mean of its divisors is an integer number (7570908000).
Almost surely, 2143321474055 is an apocalyptic number.
143321474055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
143321474055 is a deficient number, since it is larger than the sum of its proper divisors (98947581945).
143321474055 is a wasteful number, since it uses less digits than its factorization.
143321474055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7010183.
The product of its (nonzero) digits is 201600, while the sum is 39.
Adding to 143321474055 its reverse (550474123341), we get a palindrome (693795597396).
The spelling of 143321474055 in words is "one hundred forty-three billion, three hundred twenty-one million, four hundred seventy-four thousand, fifty-five".
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