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14333000419 is a prime number
BaseRepresentation
bin11010101100101000…
…00011101011100011
31100222220001212021101
431112110003223203
5213323222003134
610330125535231
71015120331143
oct152624035343
940886055241
1014333000419
1160956723a1
122940114517
1314755c254a
1499d7da923
1558d4aee14
hex356503ae3

14333000419 has 2 divisors, whose sum is σ = 14333000420. Its totient is φ = 14333000418.

The previous prime is 14333000411. The next prime is 14333000447. The reversal of 14333000419 is 91400033341.

14333000419 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (14333000447) can be obtained adding 14333000419 to its sum of digits (28).

It is a weak prime.

It is an emirp because it is prime and its reverse (91400033341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14333000419 - 23 = 14333000411 is a prime.

It is a super-2 number, since 2×143330004192 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14333000411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7166500209 + 7166500210.

It is an arithmetic number, because the mean of its divisors is an integer number (7166500210).

Almost surely, 214333000419 is an apocalyptic number.

14333000419 is a deficient number, since it is larger than the sum of its proper divisors (1).

14333000419 is an equidigital number, since it uses as much as digits as its factorization.

14333000419 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 28.

The spelling of 14333000419 in words is "fourteen billion, three hundred thirty-three million, four hundred nineteen", and thus it is an aban number.