143330403111242 has 16 divisors (see below), whose sum is σ = 219167355762792. Its totient is φ = 70276040452800.

The previous prime is 143330403111151. The next prime is 143330403111257. The reversal of 143330403111242 is 242111304033341.

143330403111242 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 103961291291881 + 39369111819361 = 10196141^2 + 6274481^2 .

It is a super-2 number, since 2×143330403111242² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143330403111199 and 143330403111208.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 355446473 + ... + 355849484.

Almost surely, 2^{143330403111242} is an apocalyptic number.

143330403111242 is a deficient number, since it is larger than the sum of its proper divisors (75836952651550).

143330403111242 is a wasteful number, since it uses less digits than its factorization.

143330403111242 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 711297913.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 143330403111242 its reverse (242111304033341), we get a palindrome (385441707144583).

The spelling of 143330403111242 in words is "one hundred forty-three trillion, three hundred thirty billion, four hundred three million, one hundred eleven thousand, two hundred forty-two".