Base | Representation |
---|---|
bin | 100000100101110010011010… |
… | …000011011101011000011101 |
3 | 200210111121201011020121002112 |
4 | 200211302122003131120131 |
5 | 122241342002144401112 |
6 | 1224502500540003405 |
7 | 42122361626623016 |
oct | 4045623203353035 |
9 | 623447634217075 |
10 | 143334233200157 |
11 | 41741785a2017a |
12 | 140ab174830565 |
13 | 61c948b46574c |
14 | 27575b1a6a00d |
15 | 11886bb9a4a22 |
hex | 825c9a0dd61d |
143334233200157 has 2 divisors, whose sum is σ = 143334233200158. Its totient is φ = 143334233200156.
The previous prime is 143334233200117. The next prime is 143334233200181. The reversal of 143334233200157 is 751002332433341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 106143031025476 + 37191202174681 = 10302574^2 + 6098459^2 .
It is a cyclic number.
It is not a de Polignac number, because 143334233200157 - 214 = 143334233183773 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143334233200117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71667116600078 + 71667116600079.
It is an arithmetic number, because the mean of its divisors is an integer number (71667116600079).
Almost surely, 2143334233200157 is an apocalyptic number.
It is an amenable number.
143334233200157 is a deficient number, since it is larger than the sum of its proper divisors (1).
143334233200157 is an equidigital number, since it uses as much as digits as its factorization.
143334233200157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 41.
Adding to 143334233200157 its reverse (751002332433341), we get a palindrome (894336565633498).
The spelling of 143334233200157 in words is "one hundred forty-three trillion, three hundred thirty-four billion, two hundred thirty-three million, two hundred thousand, one hundred fifty-seven".
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