Base | Representation |
---|---|
bin | 1101000010010110011011… |
… | …1100100010110101000111 |
3 | 1212202022122101222020010212 |
4 | 3100211212330202311013 |
5 | 3334322044422422322 |
6 | 50252544105510035 |
7 | 3006412462206353 |
oct | 320454674426507 |
9 | 55668571866125 |
10 | 14334033014087 |
11 | 4627035a49106 |
12 | 17360467a231b |
13 | 7cc9028581c7 |
14 | 377ab14c4463 |
15 | 19ccdb2cd0e2 |
hex | d0966f22d47 |
14334033014087 has 2 divisors, whose sum is σ = 14334033014088. Its totient is φ = 14334033014086.
The previous prime is 14334033014071. The next prime is 14334033014111. The reversal of 14334033014087 is 78041033043341.
14334033014087 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (78041033043341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14334033014087 - 24 = 14334033014071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14334033014887) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7167016507043 + 7167016507044.
It is an arithmetic number, because the mean of its divisors is an integer number (7167016507044).
Almost surely, 214334033014087 is an apocalyptic number.
14334033014087 is a deficient number, since it is larger than the sum of its proper divisors (1).
14334033014087 is an equidigital number, since it uses as much as digits as its factorization.
14334033014087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 290304, while the sum is 41.
The spelling of 14334033014087 in words is "fourteen trillion, three hundred thirty-four billion, thirty-three million, fourteen thousand, eighty-seven".
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