Base | Representation |
---|---|
bin | 100000100101111000010111… |
… | …100100110010001101110111 |
3 | 200210112020020020120201222112 |
4 | 200211320113210302031313 |
5 | 122241443104304234133 |
6 | 1224505440032321235 |
7 | 42123006352165001 |
oct | 4045702744621567 |
9 | 623466206521875 |
10 | 143340634055543 |
11 | 41744470050601 |
12 | 140b04603a321b |
13 | 61c9c6b5b2242 |
14 | 2757a1bbc3371 |
15 | 11889438be648 |
hex | 825e17932377 |
143340634055543 has 2 divisors, whose sum is σ = 143340634055544. Its totient is φ = 143340634055542.
The previous prime is 143340634055513. The next prime is 143340634055621. The reversal of 143340634055543 is 345550436043341.
143340634055543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-143340634055543 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 143340634055491 and 143340634055500.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143340634055513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71670317027771 + 71670317027772.
It is an arithmetic number, because the mean of its divisors is an integer number (71670317027772).
Almost surely, 2143340634055543 is an apocalyptic number.
143340634055543 is a deficient number, since it is larger than the sum of its proper divisors (1).
143340634055543 is an equidigital number, since it uses as much as digits as its factorization.
143340634055543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552000, while the sum is 50.
The spelling of 143340634055543 in words is "one hundred forty-three trillion, three hundred forty billion, six hundred thirty-four million, fifty-five thousand, five hundred forty-three".
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