Base | Representation |
---|---|
bin | 1000010101111111011… |
… | …0111010110100110011 |
3 | 111200222202112211210001 |
4 | 2011133312322310303 |
5 | 4322031042344021 |
6 | 145503411450431 |
7 | 13233103124431 |
oct | 2053766726463 |
9 | 450882484701 |
10 | 143342153011 |
11 | 558779aa172 |
12 | 23944bb6a17 |
13 | 10695112b25 |
14 | 6d1b45bd51 |
15 | 3ade34e091 |
hex | 215fdbad33 |
143342153011 has 2 divisors, whose sum is σ = 143342153012. Its totient is φ = 143342153010.
The previous prime is 143342152999. The next prime is 143342153039. The reversal of 143342153011 is 110351243341.
It is an a-pointer prime, because the next prime (143342153039) can be obtained adding 143342153011 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 143342153011 - 27 = 143342152883 is a prime.
It is a super-2 number, since 2×1433421530112 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (143342153041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71671076505 + 71671076506.
It is an arithmetic number, because the mean of its divisors is an integer number (71671076506).
Almost surely, 2143342153011 is an apocalyptic number.
143342153011 is a deficient number, since it is larger than the sum of its proper divisors (1).
143342153011 is an equidigital number, since it uses as much as digits as its factorization.
143342153011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 143342153011 its reverse (110351243341), we get a palindrome (253693396352).
The spelling of 143342153011 in words is "one hundred forty-three billion, three hundred forty-two million, one hundred fifty-three thousand, eleven".
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