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14336120372117 is a prime number
BaseRepresentation
bin1101000010011110001101…
…0111001011101110010101
31212202112000212201000001112
43100213203113023232111
53334340333303401432
650253531153104405
73006515266361315
oct320474327135625
955675025630045
1014336120372117
114627a07232095
121736529858105
137ccb7613aabb
14377c2c7dd445
1519cdae6997b2
hexd09e35cbb95

14336120372117 has 2 divisors, whose sum is σ = 14336120372118. Its totient is φ = 14336120372116.

The previous prime is 14336120372023. The next prime is 14336120372201. The reversal of 14336120372117 is 71127302163341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14332879802641 + 3240569476 = 3785879^2 + 56926^2 .

It is a cyclic number.

It is not a de Polignac number, because 14336120372117 - 212 = 14336120368021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14336120374117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7168060186058 + 7168060186059.

It is an arithmetic number, because the mean of its divisors is an integer number (7168060186059).

Almost surely, 214336120372117 is an apocalyptic number.

It is an amenable number.

14336120372117 is a deficient number, since it is larger than the sum of its proper divisors (1).

14336120372117 is an equidigital number, since it uses as much as digits as its factorization.

14336120372117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 127008, while the sum is 41.

The spelling of 14336120372117 in words is "fourteen trillion, three hundred thirty-six billion, one hundred twenty million, three hundred seventy-two thousand, one hundred seventeen".