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143380477337 is a prime number
BaseRepresentation
bin1000010110001000100…
…1000111010110011001
3111201002102122220212112
42011202021013112121
54322120400233322
6145511301122105
713234046643236
oct2054211072631
9451072586775
10143380477337
11558975a5869
12239559b9335
13106a0040a46
146d2259678d
153ae28be5e2
hex2162247599

143380477337 has 2 divisors, whose sum is σ = 143380477338. Its totient is φ = 143380477336.

The previous prime is 143380477321. The next prime is 143380477343. The reversal of 143380477337 is 733774083341.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90784100416 + 52596376921 = 301304^2 + 229339^2 .

It is a cyclic number.

It is not a de Polignac number, because 143380477337 - 24 = 143380477321 is a prime.

It is a super-2 number, since 2×1433804773372 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (143380471337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71690238668 + 71690238669.

It is an arithmetic number, because the mean of its divisors is an integer number (71690238669).

Almost surely, 2143380477337 is an apocalyptic number.

It is an amenable number.

143380477337 is a deficient number, since it is larger than the sum of its proper divisors (1).

143380477337 is an equidigital number, since it uses as much as digits as its factorization.

143380477337 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3556224, while the sum is 50.

The spelling of 143380477337 in words is "one hundred forty-three billion, three hundred eighty million, four hundred seventy-seven thousand, three hundred thirty-seven".