14340042511313 has 2 divisors, whose sum is σ = 14340042511314. Its totient is φ = 14340042511312.

The previous prime is 14340042511297. The next prime is 14340042511321. The reversal of 14340042511313 is 31311524004341.

14340042511313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12967611517249 + 1372430994064 = 3601057^2 + 1171508^2 .

It is a cyclic number.

It is not a de Polignac number, because 14340042511313 - 2⁴ = 14340042511297 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14340042511313.

It is not a weakly prime, because it can be changed into another prime (14340042511813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170021255656 + 7170021255657.

It is an arithmetic number, because the mean of its divisors is an integer number (7170021255657).

Almost surely, 2^{14340042511313} is an apocalyptic number.

It is an amenable number.

14340042511313 is a deficient number, since it is larger than the sum of its proper divisors (1).

14340042511313 is an equidigital number, since it uses as much as digits as its factorization.

14340042511313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 14340042511313 its reverse (31311524004341), we get a palindrome (45651566515654).

The spelling of 14340042511313 in words is "fourteen trillion, three hundred forty billion, forty-two million, five hundred eleven thousand, three hundred thirteen".