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143402300201 is a prime number
BaseRepresentation
bin1000010110001101110…
…0010111001100101001
3111201010221201122012202
42011203130113030221
54322141442101301
6145513400545545
713234433303606
oct2054334271451
9451127648182
10143402300201
11558a8950696
12239611822b5
13106a4711a94
146d254376ad
153ae478066b
hex2163717329

143402300201 has 2 divisors, whose sum is σ = 143402300202. Its totient is φ = 143402300200.

The previous prime is 143402300189. The next prime is 143402300203. The reversal of 143402300201 is 102003204341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 143231971600 + 170328601 = 378460^2 + 13051^2 .

It is an emirp because it is prime and its reverse (102003204341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143402300201 - 218 = 143402038057 is a prime.

Together with 143402300203, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (143402300203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71701150100 + 71701150101.

It is an arithmetic number, because the mean of its divisors is an integer number (71701150101).

Almost surely, 2143402300201 is an apocalyptic number.

It is an amenable number.

143402300201 is a deficient number, since it is larger than the sum of its proper divisors (1).

143402300201 is an equidigital number, since it uses as much as digits as its factorization.

143402300201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 143402300201 its reverse (102003204341), we get a palindrome (245405504542).

The spelling of 143402300201 in words is "one hundred forty-three billion, four hundred two million, three hundred thousand, two hundred one".