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14340295243733 is a prime number
BaseRepresentation
bin1101000010101101110000…
…1101000011011111010101
31212202220210211110110021012
43100223130031003133111
53334422411040244413
650255501331102005
73010023612243554
oct320533415033725
955686724413235
1014340295243733
1146297598a5a08
1217372b3a41905
13800390059034
14378107073d9b
1519d055e637a8
hexd0adc3437d5

14340295243733 has 2 divisors, whose sum is σ = 14340295243734. Its totient is φ = 14340295243732.

The previous prime is 14340295243649. The next prime is 14340295243759. The reversal of 14340295243733 is 33734259204341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14014713166129 + 325582077604 = 3743623^2 + 570598^2 .

It is an emirp because it is prime and its reverse (33734259204341) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14340295243733 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14340295249733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170147621866 + 7170147621867.

It is an arithmetic number, because the mean of its divisors is an integer number (7170147621867).

Almost surely, 214340295243733 is an apocalyptic number.

It is an amenable number.

14340295243733 is a deficient number, since it is larger than the sum of its proper divisors (1).

14340295243733 is an equidigital number, since it uses as much as digits as its factorization.

14340295243733 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6531840, while the sum is 50.

The spelling of 14340295243733 in words is "fourteen trillion, three hundred forty billion, two hundred ninety-five million, two hundred forty-three thousand, seven hundred thirty-three".