Base | Representation |
---|---|
bin | 10100110111100010111… |
… | …100010000001001001011 |
3 | 12002002111010100220211021 |
4 | 110313202330100021023 |
5 | 141443344034231042 |
6 | 3014441321013311 |
7 | 205414432046002 |
oct | 24674274201113 |
9 | 5062433326737 |
10 | 1434031555147 |
11 | 503195478384 |
12 | 1b1b12324237 |
13 | a52c82bb459 |
14 | 4d59c25dc39 |
15 | 27480b93867 |
hex | 14de2f1024b |
1434031555147 has 2 divisors, whose sum is σ = 1434031555148. Its totient is φ = 1434031555146.
The previous prime is 1434031555093. The next prime is 1434031555189. The reversal of 1434031555147 is 7415551304341.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1434031555147 - 235 = 1399671816779 is a prime.
It is not a weakly prime, because it can be changed into another prime (1434031555447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717015777573 + 717015777574.
It is an arithmetic number, because the mean of its divisors is an integer number (717015777574).
Almost surely, 21434031555147 is an apocalyptic number.
1434031555147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1434031555147 is an equidigital number, since it uses as much as digits as its factorization.
1434031555147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504000, while the sum is 43.
Adding to 1434031555147 its reverse (7415551304341), we get a palindrome (8849582859488).
The spelling of 1434031555147 in words is "one trillion, four hundred thirty-four billion, thirty-one million, five hundred fifty-five thousand, one hundred forty-seven".
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