Base | Representation |
---|---|
bin | 1101000010110000110011… |
… | …1001101001111101111101 |
3 | 1212202222220202210021020221 |
4 | 3100230030321221331331 |
5 | 3334431044213221140 |
6 | 50300114354141341 |
7 | 3010053062515051 |
oct | 320541471517575 |
9 | 55688822707227 |
10 | 14341112242045 |
11 | 462a038a96926 |
12 | 17374a1581851 |
13 | 8004903b0ca4 |
14 | 378183785c61 |
15 | 19d0a2a4714a |
hex | d0b0ce69f7d |
14341112242045 has 32 divisors (see below), whose sum is σ = 17471982528000. Its totient is φ = 11298558036480.
The previous prime is 14341112242043. The next prime is 14341112242049. The reversal of 14341112242045 is 54024221114341.
It is not a de Polignac number, because 14341112242045 - 21 = 14341112242043 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14341112242045.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14341112242043) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 496922826 + ... + 496951684.
It is an arithmetic number, because the mean of its divisors is an integer number (545999454000).
Almost surely, 214341112242045 is an apocalyptic number.
It is an amenable number.
14341112242045 is a deficient number, since it is larger than the sum of its proper divisors (3130870285955).
14341112242045 is a wasteful number, since it uses less digits than its factorization.
14341112242045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32133.
The product of its (nonzero) digits is 30720, while the sum is 34.
Adding to 14341112242045 its reverse (54024221114341), we get a palindrome (68365333356386).
The spelling of 14341112242045 in words is "fourteen trillion, three hundred forty-one billion, one hundred twelve million, two hundred forty-two thousand, forty-five".
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