Base | Representation |
---|---|
bin | 1101000010110000110011… |
… | …1001101101001100010011 |
3 | 1212202222220202210221101001 |
4 | 3100230030321231030103 |
5 | 3334431044214132001 |
6 | 50300114354322431 |
7 | 3010053062601415 |
oct | 320541471551423 |
9 | 55688822727331 |
10 | 14341112255251 |
11 | 462a038aa5841 |
12 | 17374a1589417 |
13 | 8004903b6cc2 |
14 | 37818378a9b5 |
15 | 19d0a2a4b001 |
hex | d0b0ce6d313 |
14341112255251 has 2 divisors, whose sum is σ = 14341112255252. Its totient is φ = 14341112255250.
The previous prime is 14341112255233. The next prime is 14341112255273. The reversal of 14341112255251 is 15255221114341.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14341112255251 - 211 = 14341112253203 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14341112255251.
It is not a weakly prime, because it can be changed into another prime (14341112255291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170556127625 + 7170556127626.
It is an arithmetic number, because the mean of its divisors is an integer number (7170556127626).
Almost surely, 214341112255251 is an apocalyptic number.
14341112255251 is a deficient number, since it is larger than the sum of its proper divisors (1).
14341112255251 is an equidigital number, since it uses as much as digits as its factorization.
14341112255251 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 48000, while the sum is 37.
Adding to 14341112255251 its reverse (15255221114341), we get a palindrome (29596333369592).
The spelling of 14341112255251 in words is "fourteen trillion, three hundred forty-one billion, one hundred twelve million, two hundred fifty-five thousand, two hundred fifty-one".
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