Base | Representation |
---|---|
bin | 1101000010110000110011… |
… | …1001101101001110100111 |
3 | 1212202222220202210221120112 |
4 | 3100230030321231032213 |
5 | 3334431044214133044 |
6 | 50300114354323235 |
7 | 3010053062602016 |
oct | 320541471551647 |
9 | 55688822727515 |
10 | 14341112255399 |
11 | 462a038aa5966 |
12 | 17374a158951b |
13 | 8004903b70a7 |
14 | 37818378aa7d |
15 | 19d0a2a4b09e |
hex | d0b0ce6d3a7 |
14341112255399 has 2 divisors, whose sum is σ = 14341112255400. Its totient is φ = 14341112255398.
The previous prime is 14341112255329. The next prime is 14341112255413. The reversal of 14341112255399 is 99355221114341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14341112255399 - 220 = 14341111206823 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14341112255329) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170556127699 + 7170556127700.
It is an arithmetic number, because the mean of its divisors is an integer number (7170556127700).
Almost surely, 214341112255399 is an apocalyptic number.
14341112255399 is a deficient number, since it is larger than the sum of its proper divisors (1).
14341112255399 is an equidigital number, since it uses as much as digits as its factorization.
14341112255399 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1166400, while the sum is 50.
The spelling of 14341112255399 in words is "fourteen trillion, three hundred forty-one billion, one hundred twelve million, two hundred fifty-five thousand, three hundred ninety-nine".
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