14341112313131 has 2 divisors, whose sum is σ = 14341112313132. Its totient is φ = 14341112313130.

The previous prime is 14341112313083. The next prime is 14341112313137. The reversal of 14341112313131 is 13131321114341.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14341112313131 - 2⁶ = 14341112313067 is a prime.

It is a super-2 number, since 2×14341112313131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14341112313094 and 14341112313103.

It is not a weakly prime, because it can be changed into another prime (14341112313137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170556156565 + 7170556156566.

It is an arithmetic number, because the mean of its divisors is an integer number (7170556156566).

Almost surely, 2^{14341112313131} is an apocalyptic number.

14341112313131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14341112313131 is an equidigital number, since it uses as much as digits as its factorization.

14341112313131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2592, while the sum is 29.

Adding to 14341112313131 its reverse (13131321114341), we get a palindrome (27472433427472).

The spelling of 14341112313131 in words is "fourteen trillion, three hundred forty-one billion, one hundred twelve million, three hundred thirteen thousand, one hundred thirty-one".