14341142113 has 2 divisors, whose sum is σ = 14341142114. Its totient is φ = 14341142112.

The previous prime is 14341142093. The next prime is 14341142131. The reversal of 14341142113 is 31124114341.

Together with next prime (14341142131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8414759824 + 5926382289 = 91732^2 + 76983^2 .

It is an emirp because it is prime and its reverse (31124114341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14341142113 - 2²⁵ = 14307587681 is a prime.

It is not a weakly prime, because it can be changed into another prime (14341142143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170571056 + 7170571057.

It is an arithmetic number, because the mean of its divisors is an integer number (7170571057).

Almost surely, 2^14341142113 is an apocalyptic number.

It is an amenable number.

14341142113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14341142113 is an equidigital number, since it uses as much as digits as its factorization.

14341142113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 25.

Adding to 14341142113 its reverse (31124114341), we get a palindrome (45465256454).

The spelling of 14341142113 in words is "fourteen billion, three hundred forty-one million, one hundred forty-two thousand, one hundred thirteen".