14341144171253 has 2 divisors, whose sum is σ = 14341144171254. Its totient is φ = 14341144171252.

The previous prime is 14341144171231. The next prime is 14341144171273. The reversal of 14341144171253 is 35217144114341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9062881453444 + 5278262717809 = 3010462^2 + 2297447^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14341144171253 is a prime.

It is a super-2 number, since 2×14341144171253² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14341144171253.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14341144171213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170572085626 + 7170572085627.

It is an arithmetic number, because the mean of its divisors is an integer number (7170572085627).

Almost surely, 2^{14341144171253} is an apocalyptic number.

It is an amenable number.

14341144171253 is a deficient number, since it is larger than the sum of its proper divisors (1).

14341144171253 is an equidigital number, since it uses as much as digits as its factorization.

14341144171253 is an evil number, because the sum of its binary digits is even.

The product of its digits is 161280, while the sum is 41.

Adding to 14341144171253 its reverse (35217144114341), we get a palindrome (49558288285594).

The spelling of 14341144171253 in words is "fourteen trillion, three hundred forty-one billion, one hundred forty-four million, one hundred seventy-one thousand, two hundred fifty-three".