Base | Representation |
---|---|
bin | 1101000010110000111011… |
… | …0011111101000111100101 |
3 | 1212210000000000010002022122 |
4 | 3100230032303331013211 |
5 | 3334431130420131203 |
6 | 50300121501235325 |
7 | 3010053632153342 |
oct | 320541663750745 |
9 | 55700000102278 |
10 | 14341144302053 |
11 | 462a0550a3aa8 |
12 | 17374b0262b45 |
13 | 800496c277ca |
14 | 378187b2d7c9 |
15 | 19d0a577b538 |
hex | d0b0ecfd1e5 |
14341144302053 has 2 divisors, whose sum is σ = 14341144302054. Its totient is φ = 14341144302052.
The previous prime is 14341144302041. The next prime is 14341144302229. The reversal of 14341144302053 is 35020344114341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12737025796609 + 1604118505444 = 3568897^2 + 1266538^2 .
It is a cyclic number.
It is not a de Polignac number, because 14341144302053 - 26 = 14341144301989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14341144302853) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170572151026 + 7170572151027.
It is an arithmetic number, because the mean of its divisors is an integer number (7170572151027).
Almost surely, 214341144302053 is an apocalyptic number.
It is an amenable number.
14341144302053 is a deficient number, since it is larger than the sum of its proper divisors (1).
14341144302053 is an equidigital number, since it uses as much as digits as its factorization.
14341144302053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 14341144302053 its reverse (35020344114341), we get a palindrome (49361488416394).
The spelling of 14341144302053 in words is "fourteen trillion, three hundred forty-one billion, one hundred forty-four million, three hundred two thousand, fifty-three".
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