143412214331 has 2 divisors, whose sum is σ = 143412214332. Its totient is φ = 143412214330.

The previous prime is 143412214321. The next prime is 143412214333. The reversal of 143412214331 is 133412214341.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-143412214331 is a prime.

It is a super-3 number, since 3×143412214331³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

Together with 143412214333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 143412214294 and 143412214303.

It is not a weakly prime, because it can be changed into another prime (143412214333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71706107165 + 71706107166.

It is an arithmetic number, because the mean of its divisors is an integer number (71706107166).

Almost surely, 2^143412214331 is an apocalyptic number.

143412214331 is a deficient number, since it is larger than the sum of its proper divisors (1).

143412214331 is an equidigital number, since it uses as much as digits as its factorization.

143412214331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6912, while the sum is 29.

Adding to 143412214331 its reverse (133412214341), we get a palindrome (276824428672).

The spelling of 143412214331 in words is "one hundred forty-three billion, four hundred twelve million, two hundred fourteen thousand, three hundred thirty-one".