Base | Representation |
---|---|
bin | 10100110111101010010… |
… | …011001010000101001001 |
3 | 12002002210201122120111221 |
4 | 110313222103022011021 |
5 | 141444122140001022 |
6 | 3014501450522041 |
7 | 205420461235636 |
oct | 24675223120511 |
9 | 5062721576457 |
10 | 1434155000137 |
11 | 503249122432 |
12 | 1b1b47736321 |
13 | a5317a50422 |
14 | 4d5b07d518d |
15 | 2748b929cc7 |
hex | 14dea4ca149 |
1434155000137 has 2 divisors, whose sum is σ = 1434155000138. Its totient is φ = 1434155000136.
The previous prime is 1434155000087. The next prime is 1434155000141. The reversal of 1434155000137 is 7310005514341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1370910797881 + 63244202256 = 1170859^2 + 251484^2 .
It is a cyclic number.
It is not a de Polignac number, because 1434155000137 - 215 = 1434154967369 is a prime.
It is not a weakly prime, because it can be changed into another prime (1434155000177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717077500068 + 717077500069.
It is an arithmetic number, because the mean of its divisors is an integer number (717077500069).
Almost surely, 21434155000137 is an apocalyptic number.
It is an amenable number.
1434155000137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1434155000137 is an equidigital number, since it uses as much as digits as its factorization.
1434155000137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25200, while the sum is 34.
The spelling of 1434155000137 in words is "one trillion, four hundred thirty-four billion, one hundred fifty-five million, one hundred thirty-seven", and thus it is an aban number.
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