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1434211034654 = 210137319034999
BaseRepresentation
bin10100110111101101101…
…000111010011000011110
312002002221122002102102102
4110313231220322120132
5141444231011102104
63014511211525102
7205422041435606
oct24675550723036
95062848072372
101434211034654
11503277814a52
121b1b62459792
13a532653c448
144d5b801dc06
15274917e7a1e
hex14deda3a61e

1434211034654 has 16 divisors (see below), whose sum is σ = 2178441540000. Its totient is φ = 708101925600.

The previous prime is 1434211034639. The next prime is 1434211034657. The reversal of 1434211034654 is 4564301124341.

It is a super-2 number, since 2×14342110346542 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1434211034657) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9442154 + ... + 9592845.

It is an arithmetic number, because the mean of its divisors is an integer number (136152596250).

Almost surely, 21434211034654 is an apocalyptic number.

1434211034654 is a deficient number, since it is larger than the sum of its proper divisors (744230505346).

1434211034654 is a wasteful number, since it uses less digits than its factorization.

1434211034654 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19035475.

The product of its (nonzero) digits is 138240, while the sum is 38.

Adding to 1434211034654 its reverse (4564301124341), we get a palindrome (5998512158995).

The spelling of 1434211034654 in words is "one trillion, four hundred thirty-four billion, two hundred eleven million, thirty-four thousand, six hundred fifty-four".

Divisors: 1 2 101 202 373 746 37673 75346 19034999 38069998 1922534899 3845069798 7100054627 14200109254 717105517327 1434211034654