Base | Representation |
---|---|
bin | 1000010110010010110… |
… | …0001110000001000101 |
3 | 111201012102010012010222 |
4 | 2011210230032001011 |
5 | 4322212321442432 |
6 | 145515425354125 |
7 | 13235106242462 |
oct | 2054454160105 |
9 | 451172105128 |
10 | 143423234117 |
11 | 55909749649 |
12 | 23968198945 |
13 | 106a8b61307 |
14 | 6d28126669 |
15 | 3ae6518112 |
hex | 2164b0e045 |
143423234117 has 2 divisors, whose sum is σ = 143423234118. Its totient is φ = 143423234116.
The previous prime is 143423234089. The next prime is 143423234167. The reversal of 143423234117 is 711432324341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 91781126116 + 51642108001 = 302954^2 + 227249^2 .
It is an emirp because it is prime and its reverse (711432324341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 143423234117 - 220 = 143422185541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143423234167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71711617058 + 71711617059.
It is an arithmetic number, because the mean of its divisors is an integer number (71711617059).
Almost surely, 2143423234117 is an apocalyptic number.
It is an amenable number.
143423234117 is a deficient number, since it is larger than the sum of its proper divisors (1).
143423234117 is an equidigital number, since it uses as much as digits as its factorization.
143423234117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 48384, while the sum is 35.
Adding to 143423234117 its reverse (711432324341), we get a palindrome (854855558458).
The spelling of 143423234117 in words is "one hundred forty-three billion, four hundred twenty-three million, two hundred thirty-four thousand, one hundred seventeen".
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