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14343001321447 is a prime number
BaseRepresentation
bin1101000010110111110101…
…1111111010111111100111
31212210011210102102110000201
43100231331133322333213
53334443431314241242
650301030035451331
73010150641442141
oct320557537727747
955704712373021
1014343001321447
11462a918363177
12173792a156b47
1380070188cc56
143782c2609c91
1519d1637e94b7
hexd0b7d7fafe7

14343001321447 has 2 divisors, whose sum is σ = 14343001321448. Its totient is φ = 14343001321446.

The previous prime is 14343001321421. The next prime is 14343001321457. The reversal of 14343001321447 is 74412310034341.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14343001321447 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14343001321457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171500660723 + 7171500660724.

It is an arithmetic number, because the mean of its divisors is an integer number (7171500660724).

Almost surely, 214343001321447 is an apocalyptic number.

14343001321447 is a deficient number, since it is larger than the sum of its proper divisors (1).

14343001321447 is an equidigital number, since it uses as much as digits as its factorization.

14343001321447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96768, while the sum is 37.

Adding to 14343001321447 its reverse (74412310034341), we get a palindrome (88755311355788).

The spelling of 14343001321447 in words is "fourteen trillion, three hundred forty-three billion, one million, three hundred twenty-one thousand, four hundred forty-seven".