Base | Representation |
---|---|
bin | 10100110111110100010… |
… | …001010111000111110111 |
3 | 12002010020101110100202011 |
4 | 110313310101113013313 |
5 | 141444443002121211 |
6 | 3014530224425051 |
7 | 205424562254545 |
oct | 24676421270767 |
9 | 5063211410664 |
10 | 1434322301431 |
11 | 503324601368 |
12 | 1b1b93778187 |
13 | a53435c9286 |
14 | 4d5c8b04d95 |
15 | 2749b475921 |
hex | 14df44571f7 |
1434322301431 has 2 divisors, whose sum is σ = 1434322301432. Its totient is φ = 1434322301430.
The previous prime is 1434322301371. The next prime is 1434322301443. The reversal of 1434322301431 is 1341032234341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1434322301431 - 211 = 1434322299383 is a prime.
It is a super-2 number, since 2×14343223014312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1434322301393 and 1434322301402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1434322301471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717161150715 + 717161150716.
It is an arithmetic number, because the mean of its divisors is an integer number (717161150716).
Almost surely, 21434322301431 is an apocalyptic number.
1434322301431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1434322301431 is an equidigital number, since it uses as much as digits as its factorization.
1434322301431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 1434322301431 its reverse (1341032234341), we get a palindrome (2775354535772).
The spelling of 1434322301431 in words is "one trillion, four hundred thirty-four billion, three hundred twenty-two million, three hundred one thousand, four hundred thirty-one".
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