Base | Representation |
---|---|
bin | 1101000010111000111110… |
… | …0011110100011110100100 |
3 | 1212210012120112121001000222 |
4 | 3100232033203310132210 |
5 | 3340000041402130340 |
6 | 50301120102223512 |
7 | 3010161311134322 |
oct | 320561743643644 |
9 | 55705515531028 |
10 | 14343304333220 |
11 | 462aa63404425 |
12 | 17379b3724b98 |
13 | 80074c5a3865 |
14 | 378310964d12 |
15 | 19d1802008b5 |
hex | d0b8f8f47a4 |
14343304333220 has 48 divisors (see below), whose sum is σ = 31706640840000. Its totient is φ = 5435290719360.
The previous prime is 14343304333207. The next prime is 14343304333243. The reversal of 14343304333220 is 2233340334341.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39910730 + ... + 40268510.
It is an arithmetic number, because the mean of its divisors is an integer number (660555017500).
Almost surely, 214343304333220 is an apocalyptic number.
14343304333220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14343304333220 is an abundant number, since it is smaller than the sum of its proper divisors (17363336506780).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14343304333220 is a wasteful number, since it uses less digits than its factorization.
14343304333220 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 463308 (or 463306 counting only the distinct ones).
The product of its (nonzero) digits is 186624, while the sum is 35.
Adding to 14343304333220 its reverse (2233340334341), we get a palindrome (16576644667561).
The spelling of 14343304333220 in words is "fourteen trillion, three hundred forty-three billion, three hundred four million, three hundred thirty-three thousand, two hundred twenty".
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