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1434331203310 = 25143433120331
BaseRepresentation
bin10100110111110100110…
…011010100011011101110
312002010021000012121211101
4110313310303110123232
5142000002242001220
63014531143313314
7205425031031545
oct24676463243356
95063230177741
101434331203310
11503329631495
121b1b9674b83a
13a53453c5065
144d5c9d8115c
152749c13330a
hex14df4cd46ee

1434331203310 has 8 divisors (see below), whose sum is σ = 2581796165976. Its totient is φ = 573732481320.

The previous prime is 1434331203251. The next prime is 1434331203379. The reversal of 1434331203310 is 133021334341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×14343312033102 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71716560156 + ... + 71716560175.

It is an arithmetic number, because the mean of its divisors is an integer number (322724520747).

Almost surely, 21434331203310 is an apocalyptic number.

1434331203310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1434331203310 is a deficient number, since it is larger than the sum of its proper divisors (1147464962666).

1434331203310 is a wasteful number, since it uses less digits than its factorization.

1434331203310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 143433120338.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 1434331203310 its reverse (133021334341), we get a palindrome (1567352537651).

The spelling of 1434331203310 in words is "one trillion, four hundred thirty-four billion, three hundred thirty-one million, two hundred three thousand, three hundred ten".

Divisors: 1 2 5 10 143433120331 286866240662 717165601655 1434331203310