Base | Representation |
---|---|
bin | 10100110111110100110… |
… | …011010100011011101110 |
3 | 12002010021000012121211101 |
4 | 110313310303110123232 |
5 | 142000002242001220 |
6 | 3014531143313314 |
7 | 205425031031545 |
oct | 24676463243356 |
9 | 5063230177741 |
10 | 1434331203310 |
11 | 503329631495 |
12 | 1b1b9674b83a |
13 | a53453c5065 |
14 | 4d5c9d8115c |
15 | 2749c13330a |
hex | 14df4cd46ee |
1434331203310 has 8 divisors (see below), whose sum is σ = 2581796165976. Its totient is φ = 573732481320.
The previous prime is 1434331203251. The next prime is 1434331203379. The reversal of 1434331203310 is 133021334341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×14343312033102 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71716560156 + ... + 71716560175.
It is an arithmetic number, because the mean of its divisors is an integer number (322724520747).
Almost surely, 21434331203310 is an apocalyptic number.
1434331203310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1434331203310 is a deficient number, since it is larger than the sum of its proper divisors (1147464962666).
1434331203310 is a wasteful number, since it uses less digits than its factorization.
1434331203310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 143433120338.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 1434331203310 its reverse (133021334341), we get a palindrome (1567352537651).
The spelling of 1434331203310 in words is "one trillion, four hundred thirty-four billion, three hundred thirty-one million, two hundred three thousand, three hundred ten".
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