143434000553413 has 2 divisors, whose sum is σ = 143434000553414. Its totient is φ = 143434000553412.

The previous prime is 143434000553341. The next prime is 143434000553419. The reversal of 143434000553413 is 314355000434341.

143434000553413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (143434000553341) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 139025252064609 + 4408748488804 = 11790897^2 + 2099702^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-143434000553413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143434000553419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71717000276706 + 71717000276707.

It is an arithmetic number, because the mean of its divisors is an integer number (71717000276707).

Almost surely, 2^{143434000553413} is an apocalyptic number.

It is an amenable number.

143434000553413 is a deficient number, since it is larger than the sum of its proper divisors (1).

143434000553413 is an equidigital number, since it uses as much as digits as its factorization.

143434000553413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 518400, while the sum is 40.

Adding to 143434000553413 its reverse (314355000434341), we get a palindrome (457789000987754).

The spelling of 143434000553413 in words is "one hundred forty-three trillion, four hundred thirty-four billion, five hundred fifty-three thousand, four hundred thirteen".