Base | Representation |
---|---|
bin | 10100110111110101100… |
… | …100101001001000000001 |
3 | 12002010021220112112012021 |
4 | 110313311210221020001 |
5 | 142000014044224441 |
6 | 3014532324401441 |
7 | 205425245653024 |
oct | 24676544511001 |
9 | 5063256475167 |
10 | 1434344133121 |
11 | 503335962889 |
12 | 1b1b9ab46281 |
13 | a5347ca1333 |
14 | 4d5cb9891bb |
15 | 2749d3393d1 |
hex | 14df5929201 |
1434344133121 has 2 divisors, whose sum is σ = 1434344133122. Its totient is φ = 1434344133120.
The previous prime is 1434344133059. The next prime is 1434344133133. The reversal of 1434344133121 is 1213314434341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 788474737521 + 645869395600 = 887961^2 + 803660^2 .
It is a cyclic number.
It is not a de Polignac number, because 1434344133121 - 215 = 1434344100353 is a prime.
It is not a weakly prime, because it can be changed into another prime (1434344233121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717172066560 + 717172066561.
It is an arithmetic number, because the mean of its divisors is an integer number (717172066561).
Almost surely, 21434344133121 is an apocalyptic number.
It is an amenable number.
1434344133121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1434344133121 is an equidigital number, since it uses as much as digits as its factorization.
1434344133121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 41472, while the sum is 34.
Adding to 1434344133121 its reverse (1213314434341), we get a palindrome (2647658567462).
The spelling of 1434344133121 in words is "one trillion, four hundred thirty-four billion, three hundred forty-four million, one hundred thirty-three thousand, one hundred twenty-one".
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