Base | Representation |
---|---|
bin | 10100110111111000111… |
… | …110110011000001001001 |
3 | 12002010102220010222021002 |
4 | 110313320332303001021 |
5 | 142000123214233113 |
6 | 3014542130224345 |
7 | 205426542025442 |
oct | 24677076630111 |
9 | 5063386128232 |
10 | 1434401321033 |
11 | 503365172a1a |
12 | 1b1bb61250b5 |
13 | a5356aa5335 |
14 | 4d5d53d42c9 |
15 | 274a3383c58 |
hex | 14df8fb3049 |
1434401321033 has 2 divisors, whose sum is σ = 1434401321034. Its totient is φ = 1434401321032.
The previous prime is 1434401320999. The next prime is 1434401321039. The reversal of 1434401321033 is 3301231044341.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1382957184064 + 51444136969 = 1175992^2 + 226813^2 .
It is a cyclic number.
It is not a de Polignac number, because 1434401321033 - 214 = 1434401304649 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1434401320987 and 1434401321005.
It is not a weakly prime, because it can be changed into another prime (1434401321039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717200660516 + 717200660517.
It is an arithmetic number, because the mean of its divisors is an integer number (717200660517).
Almost surely, 21434401321033 is an apocalyptic number.
It is an amenable number.
1434401321033 is a deficient number, since it is larger than the sum of its proper divisors (1).
1434401321033 is an equidigital number, since it uses as much as digits as its factorization.
1434401321033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 1434401321033 its reverse (3301231044341), we get a palindrome (4735632365374).
The spelling of 1434401321033 in words is "one trillion, four hundred thirty-four billion, four hundred one million, three hundred twenty-one thousand, thirty-three".
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