Search a number
-
+
14344013513 is a prime number
BaseRepresentation
bin11010101101111100…
…00100011011001001
31101000122210101101202
431112332010123021
5213334031413023
610331201553545
71015313050244
oct152676043311
941018711352
1014344013513
1160a0904725
1229439458b5
13147797a27b
149a106625b
1558e438128
hex356f846c9

14344013513 has 2 divisors, whose sum is σ = 14344013514. Its totient is φ = 14344013512.

The previous prime is 14344013491. The next prime is 14344013521. The reversal of 14344013513 is 31531044341.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9306846784 + 5037166729 = 96472^2 + 70973^2 .

It is a cyclic number.

It is not a de Polignac number, because 14344013513 - 210 = 14344012489 is a prime.

It is a super-2 number, since 2×143440135132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14344013113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7172006756 + 7172006757.

It is an arithmetic number, because the mean of its divisors is an integer number (7172006757).

Almost surely, 214344013513 is an apocalyptic number.

It is an amenable number.

14344013513 is a deficient number, since it is larger than the sum of its proper divisors (1).

14344013513 is an equidigital number, since it uses as much as digits as its factorization.

14344013513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 14344013513 its reverse (31531044341), we get a palindrome (45875057854).

The spelling of 14344013513 in words is "fourteen billion, three hundred forty-four million, thirteen thousand, five hundred thirteen".