1434421411 has 2 divisors, whose sum is σ = 1434421412. Its totient is φ = 1434421410.

The previous prime is 1434421379. The next prime is 1434421433. The reversal of 1434421411 is 1141244341.

It is a strong prime.

It is an emirp because it is prime and its reverse (1141244341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1434421411 - 2⁵ = 1434421379 is a prime.

It is not a weakly prime, because it can be changed into another prime (1434421451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717210705 + 717210706.

It is an arithmetic number, because the mean of its divisors is an integer number (717210706).

Almost surely, 2^1434421411 is an apocalyptic number.

1434421411 is a deficient number, since it is larger than the sum of its proper divisors (1).

1434421411 is an equidigital number, since it uses as much as digits as its factorization.

1434421411 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1536, while the sum is 25.

The square root of 1434421411 is about 37873.7562304031. The cubic root of 1434421411 is about 1127.7831105031.

Adding to 1434421411 its reverse (1141244341), we get a palindrome (2575665752).

The spelling of 1434421411 in words is "one billion, four hundred thirty-four million, four hundred twenty-one thousand, four hundred eleven".