Base | Representation |
---|---|
bin | 1101000010111100011000… |
… | …1000110100111111101101 |
3 | 1212210021221100120221122220 |
4 | 3100233012020310333231 |
5 | 3340003430310114313 |
6 | 50301351012225553 |
7 | 3010223100202362 |
oct | 320570610647755 |
9 | 55707840527586 |
10 | 14344220004333 |
11 | 463039326a70a |
12 | 173800a30b2b9 |
13 | 8008671c619b |
14 | 37839a400469 |
15 | 19d1d57c5823 |
hex | d0bc6234fed |
14344220004333 has 32 divisors (see below), whose sum is σ = 19224722380800. Its totient is φ = 9513382348800.
The previous prime is 14344220004259. The next prime is 14344220004403. The reversal of 14344220004333 is 33340002244341.
It is a happy number.
It is not a de Polignac number, because 14344220004333 - 29 = 14344220003821 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14344220004294 and 14344220004303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14344220004133) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1753782438 + ... + 1753790616.
It is an arithmetic number, because the mean of its divisors is an integer number (600772574400).
Almost surely, 214344220004333 is an apocalyptic number.
It is an amenable number.
14344220004333 is a deficient number, since it is larger than the sum of its proper divisors (4880502376467).
14344220004333 is a wasteful number, since it uses less digits than its factorization.
14344220004333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11393.
The product of its (nonzero) digits is 82944, while the sum is 33.
Adding to 14344220004333 its reverse (33340002244341), we get a palindrome (47684222248674).
The spelling of 14344220004333 in words is "fourteen trillion, three hundred forty-four billion, two hundred twenty million, four thousand, three hundred thirty-three".
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