Base | Representation |
---|---|
bin | 1101000010111100101110… |
… | …1001000100001101001000 |
3 | 1212210022011210100011012022 |
4 | 3100233023221010031020 |
5 | 3340004122424410240 |
6 | 50301404111304012 |
7 | 3010225301100413 |
oct | 320571351041510 |
9 | 55708153304168 |
10 | 14344312341320 |
11 | 46304303a7875 |
12 | 173803521b008 |
13 | 800880385a60 |
14 | 3783a8798b7a |
15 | 19d1dd9649b5 |
hex | d0bcba44348 |
14344312341320 has 64 divisors (see below), whose sum is σ = 34978756947120. Its totient is φ = 5262626663424.
The previous prime is 14344312341299. The next prime is 14344312341353. The reversal of 14344312341320 is 2314321344341.
It can be written as a sum of positive squares in 8 ways, for example, as 3470001486436 + 10874310854884 = 1862794^2 + 3297622^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 87769367 + ... + 87932646.
Almost surely, 214344312341320 is an apocalyptic number.
14344312341320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14344312341320 is an abundant number, since it is smaller than the sum of its proper divisors (20634444605800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14344312341320 is a wasteful number, since it uses less digits than its factorization.
14344312341320 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 175702194 (or 175702190 counting only the distinct ones).
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 14344312341320 its reverse (2314321344341), we get a palindrome (16658633685661).
The spelling of 14344312341320 in words is "fourteen trillion, three hundred forty-four billion, three hundred twelve million, three hundred forty-one thousand, three hundred twenty".
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