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143451401213 is a prime number
BaseRepresentation
bin1000010110011001011…
…1101010101111111101
3111201021101010020010202
42011212113222233331
54322242024314323
6145522313213245
713235600535341
oct2054627525775
9451241106122
10143451401213
1155923637a3a
1223975701225
13106b1943c33
146d2bb79621
153ae8c2dd28
hex21665eabfd

143451401213 has 2 divisors, whose sum is σ = 143451401214. Its totient is φ = 143451401212.

The previous prime is 143451401173. The next prime is 143451401323. The reversal of 143451401213 is 312104154341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123090108964 + 20361292249 = 350842^2 + 142693^2 .

It is a cyclic number.

It is not a de Polignac number, because 143451401213 - 210 = 143451400189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143451401113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71725700606 + 71725700607.

It is an arithmetic number, because the mean of its divisors is an integer number (71725700607).

Almost surely, 2143451401213 is an apocalyptic number.

It is an amenable number.

143451401213 is a deficient number, since it is larger than the sum of its proper divisors (1).

143451401213 is an equidigital number, since it uses as much as digits as its factorization.

143451401213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 143451401213 its reverse (312104154341), we get a palindrome (455555555554).

The spelling of 143451401213 in words is "one hundred forty-three billion, four hundred fifty-one million, four hundred one thousand, two hundred thirteen".