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143452143431 is a prime number
BaseRepresentation
bin1000010110011001101…
…0011111111101000111
3111201021102111221021022
42011212122133331013
54322242222042211
6145522341141355
713235610046262
oct2054632377507
9451242457238
10143452143431
1155923aa4643
12239759ba85b
13106b1b43a0c
146d2bccdcd9
153ae8d28bdb
hex216669ff47

143452143431 has 2 divisors, whose sum is σ = 143452143432. Its totient is φ = 143452143430.

The previous prime is 143452143421. The next prime is 143452143449. The reversal of 143452143431 is 134341254341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 143452143431 - 226 = 143385034567 is a prime.

It is a super-2 number, since 2×1434521434312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143452143391 and 143452143400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143452143421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71726071715 + 71726071716.

It is an arithmetic number, because the mean of its divisors is an integer number (71726071716).

Almost surely, 2143452143431 is an apocalyptic number.

143452143431 is a deficient number, since it is larger than the sum of its proper divisors (1).

143452143431 is an equidigital number, since it uses as much as digits as its factorization.

143452143431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 69120, while the sum is 35.

Adding to 143452143431 its reverse (134341254341), we get a palindrome (277793397772).

The spelling of 143452143431 in words is "one hundred forty-three billion, four hundred fifty-two million, one hundred forty-three thousand, four hundred thirty-one".