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14345355423439 is a prime number
BaseRepresentation
bin1101000011000000100111…
…0100000110111011001111
31212210101212111002012212101
43100300021310012323033
53340013241442022224
650302055412215531
73010263165124225
oct320601164067317
955711774065771
1014345355423439
114630916176907
12173828660a5a7
138009b84c8601
1437846711cb15
1519d250306044
hexd0c09d06ecf

14345355423439 has 2 divisors, whose sum is σ = 14345355423440. Its totient is φ = 14345355423438.

The previous prime is 14345355423431. The next prime is 14345355423461. The reversal of 14345355423439 is 93432455354341.

It is a weak prime.

It is an emirp because it is prime and its reverse (93432455354341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14345355423439 - 23 = 14345355423431 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14345355423439.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14345355423431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7172677711719 + 7172677711720.

It is an arithmetic number, because the mean of its divisors is an integer number (7172677711720).

Almost surely, 214345355423439 is an apocalyptic number.

14345355423439 is a deficient number, since it is larger than the sum of its proper divisors (1).

14345355423439 is an equidigital number, since it uses as much as digits as its factorization.

14345355423439 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 46656000, while the sum is 55.

The spelling of 14345355423439 in words is "fourteen trillion, three hundred forty-five billion, three hundred fifty-five million, four hundred twenty-three thousand, four hundred thirty-nine".