Base | Representation |
---|---|
bin | 10100111000000001111… |
… | …101110011011001100111 |
3 | 12002010211101210001221101 |
4 | 110320001331303121213 |
5 | 142000430311233044 |
6 | 3015005113100531 |
7 | 205433352164311 |
oct | 24700175633147 |
9 | 5063741701841 |
10 | 1434552055399 |
11 | 503432266981 |
12 | 1b20386b7747 |
13 | a537c0a0578 |
14 | 4d60b4307b1 |
15 | 274b170acd4 |
hex | 14e01f73667 |
1434552055399 has 2 divisors, whose sum is σ = 1434552055400. Its totient is φ = 1434552055398.
The previous prime is 1434552055393. The next prime is 1434552055411. The reversal of 1434552055399 is 9935502554341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1434552055399 - 25 = 1434552055367 is a prime.
It is a super-3 number, since 3×14345520553993 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1434552055393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717276027699 + 717276027700.
It is an arithmetic number, because the mean of its divisors is an integer number (717276027700).
Almost surely, 21434552055399 is an apocalyptic number.
1434552055399 is a deficient number, since it is larger than the sum of its proper divisors (1).
1434552055399 is an equidigital number, since it uses as much as digits as its factorization.
1434552055399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14580000, while the sum is 55.
The spelling of 1434552055399 in words is "one trillion, four hundred thirty-four billion, five hundred fifty-two million, fifty-five thousand, three hundred ninety-nine".
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