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14347074373 is a prime number
BaseRepresentation
bin11010101110010011…
…01111101101000101
31101000212112220002221
431113021233231011
5213340322334443
610331351332341
71015351056112
oct152711575505
941025486087
1014347074373
1160a2605365
1229449810b1
1314784ac528
149a1621909
1558e83eeed
hex35726fb45

14347074373 has 2 divisors, whose sum is σ = 14347074374. Its totient is φ = 14347074372.

The previous prime is 14347074337. The next prime is 14347074431. The reversal of 14347074373 is 37347074341.

Together with previous prime (14347074337) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14346529729 + 544644 = 119777^2 + 738^2 .

It is a cyclic number.

It is not a de Polignac number, because 14347074373 - 233 = 5757139781 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14347074473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7173537186 + 7173537187.

It is an arithmetic number, because the mean of its divisors is an integer number (7173537187).

Almost surely, 214347074373 is an apocalyptic number.

It is an amenable number.

14347074373 is a deficient number, since it is larger than the sum of its proper divisors (1).

14347074373 is an equidigital number, since it uses as much as digits as its factorization.

14347074373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 592704, while the sum is 43.

The spelling of 14347074373 in words is "fourteen billion, three hundred forty-seven million, seventy-four thousand, three hundred seventy-three".