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1434725311 is a prime number
BaseRepresentation
bin101010110000100…
…0010101110111111
310200222200121010111
41111201002232333
510414242202221
6354211050451
750360651425
oct12541025677
93628617114
101434725311
116769573a8
123405a0a27
1319b3194b6
14d8791115
1585e53be1
hex55842bbf

1434725311 has 2 divisors, whose sum is σ = 1434725312. Its totient is φ = 1434725310.

The previous prime is 1434725273. The next prime is 1434725333. The reversal of 1434725311 is 1135274341.

It is a strong prime.

It is an emirp because it is prime and its reverse (1135274341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1434725311 - 211 = 1434723263 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1434725371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717362655 + 717362656.

It is an arithmetic number, because the mean of its divisors is an integer number (717362656).

Almost surely, 21434725311 is an apocalyptic number.

1434725311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1434725311 is an equidigital number, since it uses as much as digits as its factorization.

1434725311 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10080, while the sum is 31.

The square root of 1434725311 is about 37877.7680308648. The cubic root of 1434725311 is about 1127.8627498345.

Adding to 1434725311 its reverse (1135274341), we get a palindrome (2569999652).

The spelling of 1434725311 in words is "one billion, four hundred thirty-four million, seven hundred twenty-five thousand, three hundred eleven".