Base | Representation |
---|---|
bin | 11010101110101010… |
… | …10111110000111011 |
3 | 1101001002021201201121 |
4 | 31113111113300323 |
5 | 213342112401133 |
6 | 10331540530111 |
7 | 1015416011335 |
oct | 152725276073 |
9 | 41032251647 |
10 | 14350122043 |
11 | 60a42a70a4 |
12 | 29459b0937 |
13 | 147900879a |
14 | 9a1bb6455 |
15 | 58ec4302d |
hex | 357557c3b |
14350122043 has 2 divisors, whose sum is σ = 14350122044. Its totient is φ = 14350122042.
The previous prime is 14350122037. The next prime is 14350122047. The reversal of 14350122043 is 34022105341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14350122043 - 25 = 14350122011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14350121999 and 14350122017.
It is not a weakly prime, because it can be changed into another prime (14350122047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7175061021 + 7175061022.
It is an arithmetic number, because the mean of its divisors is an integer number (7175061022).
Almost surely, 214350122043 is an apocalyptic number.
14350122043 is a deficient number, since it is larger than the sum of its proper divisors (1).
14350122043 is an equidigital number, since it uses as much as digits as its factorization.
14350122043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 14350122043 its reverse (34022105341), we get a palindrome (48372227384).
The spelling of 14350122043 in words is "fourteen billion, three hundred fifty million, one hundred twenty-two thousand, forty-three".
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