Base | Representation |
---|---|
bin | 1101000011010100100101… |
… | …0101001101000000000111 |
3 | 1212210220201002000021222112 |
4 | 3100311021111031000013 |
5 | 3340110231300442413 |
6 | 50304343344451235 |
7 | 3010543056415523 |
oct | 320651125150007 |
9 | 55726632007875 |
10 | 14350716030983 |
11 | 4633117093682 |
12 | 1739321919b1b |
13 | 801360c85637 |
14 | 37881504cd83 |
15 | 19d465c3e2a8 |
hex | d0d4954d007 |
14350716030983 has 2 divisors, whose sum is σ = 14350716030984. Its totient is φ = 14350716030982.
The previous prime is 14350716030913. The next prime is 14350716031009. The reversal of 14350716030983 is 38903061705341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14350716030983 - 220 = 14350714982407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14350716030913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7175358015491 + 7175358015492.
It is an arithmetic number, because the mean of its divisors is an integer number (7175358015492).
Almost surely, 214350716030983 is an apocalyptic number.
14350716030983 is a deficient number, since it is larger than the sum of its proper divisors (1).
14350716030983 is an equidigital number, since it uses as much as digits as its factorization.
14350716030983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1632960, while the sum is 50.
The spelling of 14350716030983 in words is "fourteen trillion, three hundred fifty billion, seven hundred sixteen million, thirty thousand, nine hundred eighty-three".
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