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143542097873 is a prime number
BaseRepresentation
bin1000010110101111000…
…1101001011111010001
3111201111200210002120022
42011223301221133101
54322433234112443
6145535313153225
713241051462156
oct2055361513721
9451450702508
10143542097873
115596a854759
122399bb5b815
13106c767acb5
146d39c2822d
153b01b96e68
hex216bc697d1

143542097873 has 2 divisors, whose sum is σ = 143542097874. Its totient is φ = 143542097872.

The previous prime is 143542097861. The next prime is 143542097981. The reversal of 143542097873 is 378790245341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126325508929 + 17216588944 = 355423^2 + 131212^2 .

It is an emirp because it is prime and its reverse (378790245341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143542097873 - 214 = 143542081489 is a prime.

It is a super-2 number, since 2×1435420978732 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (143542097173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71771048936 + 71771048937.

It is an arithmetic number, because the mean of its divisors is an integer number (71771048937).

Almost surely, 2143542097873 is an apocalyptic number.

It is an amenable number.

143542097873 is a deficient number, since it is larger than the sum of its proper divisors (1).

143542097873 is an equidigital number, since it uses as much as digits as its factorization.

143542097873 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5080320, while the sum is 53.

The spelling of 143542097873 in words is "one hundred forty-three billion, five hundred forty-two million, ninety-seven thousand, eight hundred seventy-three".