Base | Representation |
---|---|
bin | 11010101111001010… |
… | …00101011001101111 |
3 | 1101001101001000001120 |
4 | 31113211011121233 |
5 | 213344141204020 |
6 | 10332205112023 |
7 | 1015466015343 |
oct | 152745053157 |
9 | 41041030046 |
10 | 14354241135 |
11 | 60a665a903 |
12 | 2947258613 |
13 | 1479b1b610 |
14 | 9a2569623 |
15 | 5902a8740 |
hex | 35794566f |
14354241135 has 64 divisors (see below), whose sum is σ = 25233331200. Its totient is φ = 6924994560.
The previous prime is 14354241133. The next prime is 14354241149. The reversal of 14354241135 is 53114245341.
It is not a de Polignac number, because 14354241135 - 21 = 14354241133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14354241096 and 14354241105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14354241133) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2597175 + ... + 2602695.
It is an arithmetic number, because the mean of its divisors is an integer number (394270800).
Almost surely, 214354241135 is an apocalyptic number.
14354241135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14354241135 is a deficient number, since it is larger than the sum of its proper divisors (10879090065).
14354241135 is a wasteful number, since it uses less digits than its factorization.
14354241135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5808.
The product of its digits is 28800, while the sum is 33.
Adding to 14354241135 its reverse (53114245341), we get a palindrome (67468486476).
The spelling of 14354241135 in words is "fourteen billion, three hundred fifty-four million, two hundred forty-one thousand, one hundred thirty-five".
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