Base | Representation |
---|---|
bin | 11010101111010000… |
… | …01000011100010101 |
3 | 1101001102112120220221 |
4 | 31113220020130111 |
5 | 213344342240041 |
6 | 10332234154341 |
7 | 1015505553430 |
oct | 152750103425 |
9 | 41042476827 |
10 | 14355040021 |
11 | 60a7056043 |
12 | 29475829b1 |
13 | 147a03b12a |
14 | 9a26d6817 |
15 | 5903b52d1 |
hex | 357a08715 |
14355040021 has 4 divisors (see below), whose sum is σ = 16405760032. Its totient is φ = 12304320012.
The previous prime is 14355040003. The next prime is 14355040033. The reversal of 14355040021 is 12004055341.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14355040021 - 29 = 14355039509 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14355040121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1025359995 + ... + 1025360008.
It is an arithmetic number, because the mean of its divisors is an integer number (4101440008).
Almost surely, 214355040021 is an apocalyptic number.
It is an amenable number.
14355040021 is a deficient number, since it is larger than the sum of its proper divisors (2050720011).
14355040021 is an equidigital number, since it uses as much as digits as its factorization.
14355040021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2050720010.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 14355040021 its reverse (12004055341), we get a palindrome (26359095362).
The spelling of 14355040021 in words is "fourteen billion, three hundred fifty-five million, forty thousand, twenty-one".
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