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14355040021 = 72050720003
BaseRepresentation
bin11010101111010000…
…01000011100010101
31101001102112120220221
431113220020130111
5213344342240041
610332234154341
71015505553430
oct152750103425
941042476827
1014355040021
1160a7056043
1229475829b1
13147a03b12a
149a26d6817
155903b52d1
hex357a08715

14355040021 has 4 divisors (see below), whose sum is σ = 16405760032. Its totient is φ = 12304320012.

The previous prime is 14355040003. The next prime is 14355040033. The reversal of 14355040021 is 12004055341.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14355040021 - 29 = 14355039509 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14355040121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1025359995 + ... + 1025360008.

It is an arithmetic number, because the mean of its divisors is an integer number (4101440008).

Almost surely, 214355040021 is an apocalyptic number.

It is an amenable number.

14355040021 is a deficient number, since it is larger than the sum of its proper divisors (2050720011).

14355040021 is an equidigital number, since it uses as much as digits as its factorization.

14355040021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2050720010.

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 14355040021 its reverse (12004055341), we get a palindrome (26359095362).

The spelling of 14355040021 in words is "fourteen billion, three hundred fifty-five million, forty thousand, twenty-one".

Divisors: 1 7 2050720003 14355040021