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14355121022131 is a prime number
BaseRepresentation
bin1101000011100100111111…
…1000111010010010110011
31212211100002001210000211211
43100321033320322102303
53340143241440202011
650310352423020551
73011060165262361
oct320711770722263
955740061700754
1014355121022131
114634a7764172a
12173a150b9a757
138018b3775386
14378b120a6631
1519d622811b21
hexd0e4fe3a4b3

14355121022131 has 2 divisors, whose sum is σ = 14355121022132. Its totient is φ = 14355121022130.

The previous prime is 14355121022119. The next prime is 14355121022147. The reversal of 14355121022131 is 13122012155341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14355121022131 - 237 = 14217682068659 is a prime.

It is a super-2 number, since 2×143551210221312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14355121022093 and 14355121022102.

It is not a weakly prime, because it can be changed into another prime (14355121026131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177560511065 + 7177560511066.

It is an arithmetic number, because the mean of its divisors is an integer number (7177560511066).

Almost surely, 214355121022131 is an apocalyptic number.

14355121022131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14355121022131 is an equidigital number, since it uses as much as digits as its factorization.

14355121022131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 14355121022131 its reverse (13122012155341), we get a palindrome (27477133177472).

The spelling of 14355121022131 in words is "fourteen trillion, three hundred fifty-five billion, one hundred twenty-one million, twenty-two thousand, one hundred thirty-one".