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14355121022147 is a prime number
BaseRepresentation
bin1101000011100100111111…
…1000111010010011000011
31212211100002001210000212102
43100321033320322103003
53340143241440202042
650310352423021015
73011060165262413
oct320711770722303
955740061700772
1014355121022147
114634a77641744
12173a150b9a76b
138018b3775399
14378b120a6643
1519d622811b32
hexd0e4fe3a4c3

14355121022147 has 2 divisors, whose sum is σ = 14355121022148. Its totient is φ = 14355121022146.

The previous prime is 14355121022131. The next prime is 14355121022183. The reversal of 14355121022147 is 74122012155341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14355121022147 - 24 = 14355121022131 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14355121022147.

It is not a weakly prime, because it can be changed into another prime (14355121022647) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177560511073 + 7177560511074.

It is an arithmetic number, because the mean of its divisors is an integer number (7177560511074).

Almost surely, 214355121022147 is an apocalyptic number.

14355121022147 is a deficient number, since it is larger than the sum of its proper divisors (1).

14355121022147 is an equidigital number, since it uses as much as digits as its factorization.

14355121022147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 67200, while the sum is 38.

Adding to 14355121022147 its reverse (74122012155341), we get a palindrome (88477133177488).

The spelling of 14355121022147 in words is "fourteen trillion, three hundred fifty-five billion, one hundred twenty-one million, twenty-two thousand, one hundred forty-seven".