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14355223052351 is a prime number
BaseRepresentation
bin1101000011100101010111…
…1110001000000000111111
31212211100100011202200222212
43100321111332020000333
53340143444100133401
650310410505531035
73011062544441516
oct320712576100077
955740304680885
1014355223052351
11463501a19a525
12173a17b1a3a7b
138018cb949c9c
14378b2186567d
1519d62b767dbb
hexd0e55f8803f

14355223052351 has 2 divisors, whose sum is σ = 14355223052352. Its totient is φ = 14355223052350.

The previous prime is 14355223052341. The next prime is 14355223052371. The reversal of 14355223052351 is 15325032255341.

14355223052351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14355223052351 is a prime.

It is a super-2 number, since 2×143552230523512 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14355223052299 and 14355223052308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14355223052341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177611526175 + 7177611526176.

It is an arithmetic number, because the mean of its divisors is an integer number (7177611526176).

Almost surely, 214355223052351 is an apocalyptic number.

14355223052351 is a deficient number, since it is larger than the sum of its proper divisors (1).

14355223052351 is an equidigital number, since it uses as much as digits as its factorization.

14355223052351 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540000, while the sum is 41.

The spelling of 14355223052351 in words is "fourteen trillion, three hundred fifty-five billion, two hundred twenty-three million, fifty-two thousand, three hundred fifty-one".