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14356659260107 is a prime number
BaseRepresentation
bin1101000011101010101110…
…0100110100101011001011
31212211111001021020121122201
43100322223210310223023
53340204414232310412
650311205212501031
73011143254136243
oct320725344645313
955744037217581
1014356659260107
11463569696968a
12173a50017a777
13801a9a365168
14378c1a4c0b23
1519d6b28b0e57
hexd0eab934acb

14356659260107 has 2 divisors, whose sum is σ = 14356659260108. Its totient is φ = 14356659260106.

The previous prime is 14356659260039. The next prime is 14356659260227. The reversal of 14356659260107 is 70106295665341.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14356659260107 is a prime.

It is a super-3 number, since 3×143566592601073 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (14356659260407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7178329630053 + 7178329630054.

It is an arithmetic number, because the mean of its divisors is an integer number (7178329630054).

Almost surely, 214356659260107 is an apocalyptic number.

14356659260107 is a deficient number, since it is larger than the sum of its proper divisors (1).

14356659260107 is an equidigital number, since it uses as much as digits as its factorization.

14356659260107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8164800, while the sum is 55.

The spelling of 14356659260107 in words is "fourteen trillion, three hundred fifty-six billion, six hundred fifty-nine million, two hundred sixty thousand, one hundred seven".